hi everybody,

am building a chiller for an industrial application. please let me know if the evaporator design i've done (shown below) has any mistakes in it.


Enthalpy at evaporator entry, kJ/kg =370Enthalpy at evaporator exit, kJ/kg =270Refrigerating effect (from p-h diagram), kJ/kg =100Heat to be removed from water, kJ=4187Mass of refrigerant required, kg =41.87Specific volume of refrigerant at Evap. Temp, m3/kg=0.03911Volume of refrigerant, m3=1.637536Inner dia of the evaporator tube,m=5.72E-03Initial pull down time,hr=1Length of the evaporator, m =17.74

Am using R404a.

If there is any other easier(simpler) method please lemme know.


thanks