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Thread: Clean room ac load calculation
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14-07-2010, 04:14 PM #1
Re: Clean room ac load calculation
To determine the load you can use the following:
[Enthalpy Outside Air- Enthalpy Inside Air] x Specific Gravity of Air x Vent Rate.
As we use the SI system the conversions are as follows:
10,000 CFM = 6990.108 meters cubed/hour
96F = 35.6C
62F = 16.67C
74F = 22.78C [Since you have not stated RH = 50%]
Spec Gravity of Air = 1.2
Enthalpy Ouside Air [CIBSE Guide] 46.901
Enthalpy Inside Air [CIBSE Guide] 44.869
From formula above:
[46.910-44.869] x 1.2 x 6990.108 = 17120.173 KJ/h
Converting to Kw = 4.756.
tmm
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