Heat gains

[Magoo]

Hi Mark
Q = m [250kg ] x 4.19 x [TD ]
Q = 250 x 4.19 x 5 / 3600 seconds
= 5237.50 Kj / 3600 = 1.45 Kw [ Kj/s ]

determine flow rate 0.25Kg/sec or litres /sec = 3.3 gallons per second TOO high, more like 0.02 L/sec.

Q= 0.02 x 4.19 x 5'c td = 0.42 Kw duty

[marc5180]

Hi Mark
Q = m [250kg ] x 4.19 x [TD ]
Q = 250 x 4.19 x 5 / 3600 seconds
= 5237.50 Kj / 3600 = 1.45 Kw [ Kj/s ]
determine flow rate 0.25Kg/sec or litres /sec = 3.3 gallons per second TOO high, more like 0.02 L/sec.
Q= 0.02 x 4.19 x 5'c td = 0.42 Kw duty

Hi Magoo thanks for that.

When I was working out the cooling load originally I didn't divide by the 3600 seconds (1 hour) as I wasn't sure wether I needed to do this or even wether I should have divided by 24hours (86,400).

The flow rate of 0.02 and the KW seems much better now although the pulldown time has increased to 208mins.