Quote Originally Posted by Peter_1 View Post
Flow: 682,5/60 = 11,4 liter/s water.
This is +/- 11,4 kg/s (kcan be more precise if we use correct density, assuming 1 now)
Cooling from 7,2 down to 4,4 = 2,8ºC.
Water llooses energy : 11,4 kg/s x 4,18.10³ J/(ºCkg) x 2,8 ºC = 133,4 . 10³ J/s = 133 400 W

The question is in Imperial gallons = 4.56 l but u US gallon = 3.7854 l.
If you do the math again with 3.7854 ln, then you get 109 kW.

But,... the phormula widely used is
Q= m.c.DT
and in BTU

Btu = 500 x 150 x 5 = 375.000 btu/h

https://greenenergypro.wordpress.com...water-formula/
Q= 500 x flow rate (in gallons but which gallons???) x DT

But... for this phormula, you have to use US gallons Gallons and not Imperial gallons... I guess!!??

But BTU stands for British Thermal Unit in ...I thought ...imperial gallons...
Confusing
If the question was asked with 150 imperial gallons, then 133Kw is the correct answer.

Apparently the guy who checked the answers used US gallons and for him the answer became 109Kw...

Seems like the guy who made the exam mixed up his gallons.

I ran the numbers through our in house engineer and he also got 133 Kw

so at least I'm not stupid