Process chiller calc

[Rowan]

HI I was asked by a work mate today how a friend of his could chill a manufacturing plant he runs (at the moment he runns water from the tap through the plant and to the drain!!). I have came up with an idear of a condensing unit cooling a tank and taking the water off the bottom and through the plant (obvious). My question is 'how do I calculate the size of condensing unit and evaporator I would require'?. I guess it would be water in temp, water out temp & flow rate but what equasion? Any advise would be great

[TXiceman]

You need to know the water flow rate and the temperature in and the temp out.

Then Q=M*Cp*(T1-T2)

For water, Cp (specific heat = 1.0)
M=water mass flow.
T=Temperature.

Ken

[mohamed khamis]

HI I was asked by a work mate today how a friend of his could chill a manufacturing plant he runs (at the moment he runns water from the tap through the plant and to the drain!!). I have came up with an idear of a condensing unit cooling a tank and taking the water off the bottom and through the plant (obvious). My question is 'how do I calculate the size of condensing unit and evaporator I would require'?. I guess it would be water in temp, water out temp & flow rate but what equasion? Any advise would be great

Hi Rowan

State the details of the inlet and outlet of water and its flow rate, the ambient conditions and tank size and insulated type and size and i will calculate to u what u need..

Cheers

[Rowan]

You need to know the water flow rate and the temperature in and the temp out.

Then Q=M*Cp*(T1-T2)

For water, Cp (specific heat = 1.0)
M=water mass flow.
T=Temperature.

Ken

Thanks mate, just a few questions about the units for the calculation. Q should = KW. Do I measure the water flow rate in liters/min or liters/sec etc. Temp differance measured in 'k

[DEVITG]

Thanks mate, just a few questions about the units for the calculation. Q should = KW. Do I measure the water flow rate in liters/min or liters/sec etc. Temp differance measured in 'k

Per definition the SPECIFIC HEAT is the heat needed to rise or lower the temperature of a given mass ,
In metrics
1 [Kg] , 1 [Centigrade degree]. = 1 Calorie
Or in Imperial
1 Pound , 1 Farenheit degree = 1 BTU or Brithis therrmal unit.

As in this case we talk in metrics , the units are
Q = Calories
Cp = especific heat 1 Calorie , Kg degree
Mass = Kg = liter for water in practical

T2-T1 = degree diference or also Delta T , as Delta is the Greek letter used to mean diference between units.

1000 W = 860 Calories.

Normaly the equipmet are rated in W / Hour ,

One of the best way of having chilled water is by the use of a BRAZED PLATES HEAT EXCHANGER AS THE EVAPORATOR , but a any other mean could be used .

[TXiceman]

I work mostly in US units and have to drag the books out to convert to metric. I provided the basic formula, but you need to apply the appropriate units or conversions to suit your method.

The short cut for the US units ;;;

BTUH = 500*GPM*(T1-T2)

Ken