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  1. #1
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    Ambguity in Refrigeration tonnage of Chiller



    My model is YPC-ST-400 meaning its TonsOfRefrigeration (TR) is 400
    As can be seen we have total refrigerant (water) amount of 550kg



    Using steam tables at (~5celsius) saturated properties of water:

    Code:
    SATURATED
    Sat. pressure            0.8718 kPa ~6.5mmHg
    Sat. temperature         5.0000 C
    Quality                  1.0000
    Moisture                 0.0000
    Enthalpy
      hf                    21.0067 kJ/kg
      hfg                 2489.7275 kJ/kg
      hg                  2510.7342 kJ/kg
    Internal energy
      uf                    21.0058 kJ/kg
      ufg                 2361.4265 kJ/kg
      ug                  2382.4323 kJ/kg
    Entropy
      sf                     0.0762 kJ/kg/C
      sfg                    8.9507 kJ/kg/C
      sg                     9.0269 kJ/kg/C
    Specific volume
      vf                     0.0010 m3/kg
      vfg                  147.1621 m3/kg
      vg                   147.1631 m3/kg
    Thus at evaporator per kg water being evaporated @6.5mmHg will remove ~2489.7275kJ
    of enthalpy from the chilled water. Assuming that ~60% of 550kg water is continously
    circulated to evaporator we can calculate max. amount of enthalpy that is being
    removed & then translate it to TR ...1TR=~3.5kW ...1kJ/sec=1kW

    TR = 2489.7275kJ/kg x (550x0.6)kg/hr x 1hr/3600sec x 1TR/3.5kW = 65.2TR

    Even if I had 100% water circulation to evaporator which is nonsense I cannot get the value 400TR?



  2. #2
    Brian_UK's Avatar
    Brian_UK is offline Moderator I am starting to push the Mods: of RE Site Moderator : and general nice guy
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    Re: Ambguity in Refrigeration tonnage of Chiller

    And what is the result when using the LiBr mixture?
    Brian - Newton Abbot, Devon, UK
    Retired March 2015
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