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Thread: psychrometric chart question
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03-08-2014, 12:08 PM #1
psychrometric chart question
I'm trying to understand the following :
I have for a point :
tdb = 84.7 F
twb = 75.6 F
when i enter then [(IP units)psychro chart] to get enthalpy , it comes out to be :
h=39.1 btu/lb
now i need my enthalpy to be in (SI units) to I convert the 39.1 to be :
h= 90.94 KJ/Kg
ok , now I worked this another way ,
I transformed tdb and twb from F to C
tdb = 29.27778C
twb = 24.22222C
then entered the [(SI units)psychro chart] to get enthalpy the outcome is :
h= 73.3 KJ/Kg
I cant figure out what is the reason for the huge difference between the 73 and 90 of h in SI
can anyone help ?
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03-08-2014, 06:43 PM #2
Re: psychrometric chart question
Dude don't be an A-hole and spam, seriously
Now in Redvers Sask.
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03-08-2014, 07:18 PM #3
Re: psychrometric chart question
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03-08-2014, 10:49 PM #4
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04-08-2014, 04:41 AM #5
Re: psychrometric chart question
Thunderspeed.
search http://www.kwangu.com/work/psychrometric.htm
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04-08-2014, 03:40 PM #6
Re: psychrometric chart question
The base points are different for the (2) charts....Neither of them are working in absolute numbers, each has a different definition for "zero enthalpy". See:
http://www.engineeringtoolbox.com/en...air-d_683.html