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  1. #1
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    ReciprocatingChiller question



    photo2.jpgBeen racking my brain on these questions

    1. Approach temp=
    2.cooler flow rate=gpm
    3 RISE
    4. COOLER PRESSURE DROP = PSI


    Also what will the net refrigeration effect be if there is a fouling factor of 0.0025
    Last edited by bwd111; 07-11-2013 at 05:11 PM.



  2. #2
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    Re: ReciprocatingChiller question

    Recommend re-phrasing the question!

  3. #3
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    Re: ReciprocatingChiller question

    How would I re-phrase question

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    Re: ReciprocatingChiller question

    Quote Originally Posted by passandscore View Post
    Recommend re-phrasing the question!
    I forgot to add diagram. Sorry for ther confusion! My mistake

  5. #5
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    Re: ReciprocatingChiller question

    approach refers to SST versus water entering chiller.
    Cooler flow rate in US gallons per minute, governs the total performance on system.
    Rise refers in general to the temp change in water flowing through chiller.
    Cooler pressure drop or delta P, is a double check on water flow rate, as chiller manufacture would has publish data on flow rates at given pressure drops.
    Fouling factor is the maximum allowable fouling effect on chiller tubes, even closed circuit chilled water systems gunge up, this effects the heat transfer and reduces chiller capacity.

    magoo

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    Re: ReciprocatingChiller question

    For rise I came up with 11 degrees
    for app0roach i came up with 15 degrees
    cooler flow rate came up with 110.7 gpm
    fouling factor came up with 48 tons

    Was anybody close to my answers

  7. #7
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    Re: ReciprocatingChiller question

    using figures off drawing and stated water flow rate at 110.7 USgpm, converted to SI, I get 178.62 Kw NRE ( net/ nominal refrigeration effect ) or 50.78 tons

    OK SI metric system,,, Q (water) = L/sec x Delta TK' x specific heat 4.192 kj/kg = Kw refrig

    Cannot remember specific heat value of water in imperial.

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    Re: ReciprocatingChiller question

    Quote Originally Posted by Magoo View Post
    using figures off drawing and stated water flow rate at 110.7 USgpm, converted to SI, I get 178.62 Kw NRE ( net/ nominal refrigeration effect ) or 50.78 tons

    OK SI metric system,,, Q (water) = L/sec x Delta TK' x specific heat 4.192 kj/kg = Kw refrig

    Cannot remember specific heat value of water in imperial.
    how close were you to this answer I had cooler flow rate came up with 110.7 gpm

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