Results 1 to 5 of 5
  1. #1
    ashwininventech's Avatar
    ashwininventech Guest

    How to determine the flow?



    Hello,

    I am trying to design cooling system for an electronic heat load of the 2.5 kW in a chamber.

    I need to supply air at 17 deg C to maintain the temperature of the air in the chamber at 20 deg C. (As per the specifications)

    The chamber is insulated.

    In this case how to determine the Air Flow?



  2. #2
    Brian_UK's Avatar
    Brian_UK is offline Moderator I am starting to push the Mods: of RE Site Moderator : and general nice guy
    Join Date
    Mar 2001
    Location
    Dorset
    Age
    76
    Posts
    11,025
    Rep Power
    60

    Re: How to determine the flow?

    We need a few more details, as usual.

    Ambient air temperature
    Size of room
    Air Change Rate
    etc
    Brian - Newton Abbot, Devon, UK
    Retired March 2015

  3. #3
    ashwininventech's Avatar
    ashwininventech Guest

    Re: How to determine the flow?

    Thanks for the reply.

    Ambient air temp is 45 deg C (max)
    Size of the chamber is 520 mm (width) x 520 mm (Length) x 900 mm (Height)

  4. #4
    Join Date
    Nov 2010
    Location
    Germany
    Age
    39
    Posts
    120
    Rep Power
    14

    Re: How to determine the flow?

    Q=V*cp*ro*DT/3600
    From that
    V(air flow)=Q*3600/cp*DT*ro [m3/h]
    cp heat capacity of air
    ro density
    DT-your case 3K
    you allready have a Q=2.5kW so just change the units and that is it.
    And also you can do it according to the desired air change rate.
    Be careful about reading health books. You may die of a misprint.

  5. #5
    Join Date
    Apr 2009
    Location
    Panacea, Florida
    Age
    87
    Posts
    76
    Rep Power
    16

    Smile Re: How to determine the flow?

    KW = air flow * delta T*specific heat of air *density of air*conversion constants
    KW = L/s * ˚C * cal/gm˚C *gm/L* kw-hr/cal * s/hr
    for air, cal/gm˚C = .25, density gm/L =1.25
    s/hr = 3600, kw-hr/cal =1.163*10^-6

    so L/s = KW/(˚C * cal/gm˚C *gm/L* kw-hr/cal * s/hr )
    = 2.5/(3*.25*1.25*1.163*10^-6*3600)
    = 640 L/s

    This is the minimum air flow needed to absorb 2.5KW with a temperature rise of 3˚C. Any higher air flow will result in a chamber colder than 20˚C, ultimately approaching the 17˚C supply air temperature.
    Last edited by dougheret0; 08-02-2011 at 11:07 PM. Reason: clarify formula

Similar Threads

  1. Really weird refrigerant flow issue
    By paul_h in forum Air Conditioning
    Replies: 43
    Last Post: 13-04-2010, 05:13 PM
  2. flow switch connection
    By afeef in forum The Trail of Tears
    Replies: 18
    Last Post: 23-12-2009, 06:55 PM
  3. Flow Rate through Fan Coil Unit
    By deepu in forum Air Conditioning
    Replies: 4
    Last Post: 21-07-2009, 06:42 AM
  4. Capillary Tube Characteristics
    By Chef in forum Fundamentals
    Replies: 9
    Last Post: 10-03-2009, 01:03 PM
  5. Refrigerant flow rates/gas laws
    By budro in forum Technical Speculations
    Replies: 3
    Last Post: 24-10-2008, 03:12 AM

Posting Permissions

  • You may not post new threads
  • You may not post replies
  • You may not post attachments
  • You may not edit your posts
  •