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24-08-2009, 05:43 AM #1
Hi there i am currently doing an assignment, im trying to work out the heat load of the structure of my cold room. I have been given the following data to work with.
* The room is 15m x 10m x 5m
*The walls & ceiling are 150mm thick & are typical rollbound construction, 150mm polystyrene sandwhiched between 1mm sheet steel
*The floor is 200 mm thick , again of rollbound construction, it is standing on a 200mm concrete slab, the concrete slab is standing on the ground
*The ambient temp surrounding the room is 25 degrees celcius, The RH is 60 %
R1, Thermal resistance ,air film on outside of walls & ceiling is 0.03 W/m2/K
R2, Thermal resistance ,air film on inside of walls & ceiling is 0.12W/m2/K
R3, Thermal resistance, sheet steel 0.021W/m thick/m2/K
R4, Thermal resistance , polystyrene 28.9 W/m thick /m2/K
R5, Thermal resistance, concrete 1.07 W/m thick/m2/K
Now how would i go about working out the gain using a resistivity formula , i seem to recall it was similar to working out the resistance of an electrical circut in paralell.
Is this the formula here? resistivetey/m thick/m2/K with K being the out side ambient? then once all the equations have been solved i go R1+R2+R3+R4+r5=??
Thanks in advance if anyone can help meLast edited by chillin out; 24-08-2009 at 04:20 PM.
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