Hi, I need to cool 200 liter of water from 22°C down to 2°C in 2 hour time. How to determine how much BTU do I need in order to do that?
Thanks in advance.
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Hi, I need to cool 200 liter of water from 22°C down to 2°C in 2 hour time. How to determine how much BTU do I need in order to do that?
Thanks in advance.
mcΔt
m=mass 200ltr
c =1 for water
Δt=22-2=20
total capacity per hour = 200x1x20=4000kcal\2=2000kcal
And thats equals about 8000btuh
Q=mc(t2-t1) or Q= m*c* Δt
Q=200*1(22-2)
Q=200*20
Q=4000 Kcal
Q= 2000 Kcal/h
Q = L/sec x specific heat x delta T 'K
Q = 200/7200sec x 4.186 Kj/Kg' K x 20'K
Q = 2.3256 Kw x 3517
Q = 8178.97 Btus / hour