Does a refrigerator work better when room temp is increased????

Hello,

If i change ambient temp by 1 deg higher in my equation i get these results:

QL1 = 9639.85W; Win1 =3069W; QH1 =12708W

If I change ambient temp +1 = 25+1 degs C. and i do not change Refrigerator temp = 3deg C (unchanged), i get:

QL1 =9392.37W; Win1 = 2990W; QH1 =12382W

Ql=evap.
Win=Compressor
Qh=condenser.

So I am increasing ambient temp (room temp) by 1 deg. and keeping the refrigerator the same temp. I get reduction of evaporator heat transfer, compressor work input and also QH. COPis the same as the reductions are proportional to each other. I understand that heat flows easier where there is a bigger temp difference but still didnt expect all reductions.

Is this equation i'm using sane or insane? in respect of these results?

Please help, thank you

Looks like if there is a problem with your calculations somewhere...

Normally you would expect the work for the compressor to increase with an increased pressure differential.

It would be easier to comment if you also posted your calculations.


:cool:

Increasing the ambient temperature and in turn the condensing temperature of your refrigeration systems will cost between 2% and 4% for every 1°C increase in condensing temperature.
This will increase the compression ratio and lower the volumetric efficiency and so your equation isn't quite right.

Edit..... Just re-read your post and you say a 1degC increase in room temp. If that is the case then your SST will change, your power input will increase, your COP will increase as well as your heat of rejection.