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Hi Members
Can somebody help me with the formula to calculate the following:
In an insulated tank you get 200 liters of water at 5 Deg C and take out 50 liters from it and fill ambient temperature water ie at 35 deg C to it. What will be the new water temperature of the 200 liters.
Please let me know the formula to calculate the above. Thanks in advance for you.
Suny
((150x5)+(50x35))/200=12.5 ???
Nearly VikingQuote:
Originally Posted by The Viking
Use the formula with percentages
150 ltrs = 75% @ 5C
50 ltrs = 25% @ 35C
so it is (75 x5) + (25 x 35)/100 = 12.5C
Hi Viking & Frank
Thank you very much for your help in reminding me the formula. I studied this in physics about 35 years ago. If I need any further assistance I will contact you all.
Suny
??? Frank,
My maths teacher always told me to follow KISSQuote:
From Wikipedia, the free encyclopedia
In mathematics, a percentage is a way of expressing a number as a fraction of 100 (per cent meaning "per hundred"
(No, not the great musicians unfortunately, Keep It Simple Stupid was his motto)
The only thing you do when you convert it to percentage is to take it from a fraction based on 200 (or whatever the original total might be) to a fraction based on 100 (and adding another stage to the formula).
But HEY, at least we agree on the answer.
:cool:
If you look in Dossat the formula is expressed in percentage terms.Quote:
Originally Posted by The Viking
If you apply the formula to a mixed air condition then it would be difficult to use anything other than percentage. :)
The term which may cause confusion is "(25 x 35)/100 " so this modification will adapt what The Viking is asking about it:Quote:
Originally Posted by frank
{(75 x5) + (25 x 35)}/100 = 12.5C
Both The Viking and Frank did the same
The Viking formula
((150x5)+(50x35))/200=12.5
And Frank
150/200 = 0.75
50/200 = 0.25
Therefore
((150x5)+(50x35))/200 = 0.75x5+0.25x35 = 12.5
Cheers
looks good to meQuote:
Originally Posted by The Viking
toeMAYtoe toeMATTo frank