30°C to 20°C in one hour?

Hi all, greetings from Indonesia again...
I need to calculate how much compressor power needed for this:

I need to cool 10.000 liter (roughly 2,641 gallon) of water from 30°C (86°F) down to 20°C (68°F) within one hour.

I found this formula:

BTU = gallons x temperature change x 8.33

The result for my numbers would be... 395,991 BTU or 155 HP.
Is that number seems realistic? It seems so high, or is there a mistake?

Thank you for all your input, really appreciate it.

Regards,
Yahya.

10000l/hour = 2.8l/sec
30deg - 20deg = 10deg
specific heat capacity of water = 4.2

2.8 x 10 x 4.2 = 117.6kW of refrigerating capacity.

I don't really know what BTU's and Gallons are?:D

For getting 120 kW cooling considering 10 C evaporating and 40 condensing temperature refrigeration compressor will need around 20 to 25 kW power input depending upon which refrigerant is used.

Thank you so much for all the replies, really helps.

Quote:

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Originally Posted by sandybapat

For getting 120 kW cooling considering 10 C evaporating and 40 condensing temperature refrigeration compressor will need around 20 to 25 kW power input depending upon which refrigerant is used.

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May I know how did you came up with the number 20 to 25 kW power input? Thanks.

also
Q= MC (t2-t1)
M=10000 Kg/ h
C=1 for water

Q= 10000 * 1(30-20)
Q= 100000 cal/h

1 Kw = 860 cal

to get that you need to add %10 for safety and then you have to choose your Comp.

your evaporator temp. about 10 c ( out let temp. - delta T )

your condenser temp. about (ambient temp. + 10)

As mbc has explained I tried to select compressor 120 kW capacity with 10 deg C evaporation temp and 40 deg C condensing temperature and I got the power consumed by compressor.