heat load calculation in an enclosure

[r1sk]

Hi, I have a question on calculating the required BTUH based on these conditions. I have an enclosure with windows that houses half of two pieces equipment. The enclosure is inside a ventilated room at ambient temperature. The only info I know is the power of the equipment and the temperature that the enclosure needs to be at. I am getting a large BTUH that seems unreasonable. What is the best approach?

[The Viking]

Well,
Someone once stated that "energy can not be created nor destroyed", therefore if you know the electricity consumption of the equipment in your box you know the heat generated by it, then it is just a matter of adding any heath transfer through the walls of your box.

Amperes x Volt = Watt
Watt x 3.41214 =~ BTU

Simples...

:cool:

[r1sk]

Thanks for your response. I have done that but having trouble finding the heatloss throught the wall. my enclosure is 100ft^2 with 2 inch thick walls. Material is stainless steel. total btu/h based on the wattage is 4000.

[The Viking]

OK,
So what temperature are they looking for inside the enclosure and what is the temperature outside it?

Assuming it isn't 2" SS, it will be 2"lagging?

[r1sk]

outside is at room temperature and inside needs to be at room temperature as well

[marc5180]

What temperature is room temperature?

Or us there's no differential either side of the wall?

[marc5180]

What temperature is room temperature?

Or is there's no differential either side of the wall?

[The Viking]

So if there is no temperature differential there will be no heat transfer...

4000 is therefore your required Btu/h.

:cool: